Base | Representation |
---|---|
bin | 10100111111011110111… |
… | …111000111000010100001 |
3 | 12002220111010222101102102 |
4 | 110333132333013002201 |
5 | 142113323103130032 |
6 | 3022411202500145 |
7 | 206135601201341 |
oct | 24773677070241 |
9 | 5086433871372 |
10 | 1442555130017 |
11 | 506869844331 |
12 | 1b36b0964655 |
13 | a605614bc91 |
14 | 4db6a298d21 |
15 | 277ce112362 |
hex | 14fdefc70a1 |
1442555130017 has 2 divisors, whose sum is σ = 1442555130018. Its totient is φ = 1442555130016.
The previous prime is 1442555129969. The next prime is 1442555130059. The reversal of 1442555130017 is 7100315552441.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1437047115361 + 5508014656 = 1198769^2 + 74216^2 .
It is a cyclic number.
It is not a de Polignac number, because 1442555130017 - 28 = 1442555129761 is a prime.
It is not a weakly prime, because it can be changed into another prime (1442555930017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 721277565008 + 721277565009.
It is an arithmetic number, because the mean of its divisors is an integer number (721277565009).
Almost surely, 21442555130017 is an apocalyptic number.
It is an amenable number.
1442555130017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1442555130017 is an equidigital number, since it uses as much as digits as its factorization.
1442555130017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84000, while the sum is 38.
The spelling of 1442555130017 in words is "one trillion, four hundred forty-two billion, five hundred fifty-five million, one hundred thirty thousand, seventeen".
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