Base | Representation |
---|---|
bin | 1000011001100100011… |
… | …0100001100111111011 |
3 | 111210110200200211110122 |
4 | 2012121012201213323 |
5 | 4331012422423103 |
6 | 150143000203455 |
7 | 13265644253312 |
oct | 2063106414773 |
9 | 453420624418 |
10 | 144302545403 |
11 | 56220030195 |
12 | 23b7276958b |
13 | 107b9092c53 |
14 | 6dacc19279 |
15 | 3b48809b38 |
hex | 21991a19fb |
144302545403 has 2 divisors, whose sum is σ = 144302545404. Its totient is φ = 144302545402.
The previous prime is 144302545397. The next prime is 144302545411. The reversal of 144302545403 is 304545203441.
144302545403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 144302545403 - 26 = 144302545339 is a prime.
It is a super-3 number, since 3×1443025454033 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (144302545423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72151272701 + 72151272702.
It is an arithmetic number, because the mean of its divisors is an integer number (72151272702).
Almost surely, 2144302545403 is an apocalyptic number.
144302545403 is a deficient number, since it is larger than the sum of its proper divisors (1).
144302545403 is an equidigital number, since it uses as much as digits as its factorization.
144302545403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 115200, while the sum is 35.
Adding to 144302545403 its reverse (304545203441), we get a palindrome (448847748844).
The spelling of 144302545403 in words is "one hundred forty-four billion, three hundred two million, five hundred forty-five thousand, four hundred three".
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