Base | Representation |
---|---|
bin | 100000110100000000010010… |
… | …100110000101101011001011 |
3 | 200220222000110120022210110201 |
4 | 200310000102212011223023 |
5 | 122403343331024321303 |
6 | 1230531353414153031 |
7 | 42253066251131233 |
oct | 4064002246055313 |
9 | 626860416283421 |
10 | 144311213120203 |
11 | 41a890506912a8 |
12 | 14228591352777 |
13 | 626a6484614ac |
14 | 278c9b2a78cc3 |
15 | 11a3cec29181d |
hex | 834012985acb |
144311213120203 has 2 divisors, whose sum is σ = 144311213120204. Its totient is φ = 144311213120202.
The previous prime is 144311213120177. The next prime is 144311213120209. The reversal of 144311213120203 is 302021312113441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 144311213120203 - 225 = 144311179565771 is a prime.
It is a super-2 number, since 2×1443112131202032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (144311213120209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72155606560101 + 72155606560102.
It is an arithmetic number, because the mean of its divisors is an integer number (72155606560102).
Almost surely, 2144311213120203 is an apocalyptic number.
144311213120203 is a deficient number, since it is larger than the sum of its proper divisors (1).
144311213120203 is an equidigital number, since it uses as much as digits as its factorization.
144311213120203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 144311213120203 its reverse (302021312113441), we get a palindrome (446332525233644).
The spelling of 144311213120203 in words is "one hundred forty-four trillion, three hundred eleven billion, two hundred thirteen million, one hundred twenty thousand, two hundred three".
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