Base | Representation |
---|---|
bin | 11010111000010110… |
… | …10000000010101011 |
3 | 1101020202010210110112 |
4 | 31130023100002223 |
5 | 214023411330201 |
6 | 10344002004535 |
7 | 1020423331301 |
oct | 153413200253 |
9 | 41222123415 |
10 | 14431355051 |
11 | 613613a713 |
12 | 296904674b |
13 | 148caab159 |
14 | 9ac8c0271 |
15 | 596e3c0bb |
hex | 35c2d00ab |
14431355051 has 8 divisors (see below), whose sum is σ = 15064367664. Its totient is φ = 13811130720.
The previous prime is 14431355047. The next prime is 14431355069. The reversal of 14431355051 is 15055313441.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14431355051 - 22 = 14431355047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14431354999 and 14431355017.
It is not an unprimeable number, because it can be changed into a prime (14431355021) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3194765 + ... + 3199278.
It is an arithmetic number, because the mean of its divisors is an integer number (1883045958).
Almost surely, 214431355051 is an apocalyptic number.
14431355051 is a deficient number, since it is larger than the sum of its proper divisors (633012613).
14431355051 is an equidigital number, since it uses as much as digits as its factorization.
14431355051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6394141.
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 14431355051 its reverse (15055313441), we get a palindrome (29486668492).
The spelling of 14431355051 in words is "fourteen billion, four hundred thirty-one million, three hundred fifty-five thousand, fifty-one".
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