Base | Representation |
---|---|
bin | 1101001000000100101010… |
… | …1001001000001101000011 |
3 | 1220002201101202102222122021 |
4 | 3102001022221020031003 |
5 | 3342424414124110201 |
6 | 50410043201222311 |
7 | 3016462620245206 |
oct | 322011251101503 |
9 | 56081352388567 |
10 | 14432342410051 |
11 | 46647a4049395 |
12 | 1751102331997 |
13 | 808c6c02b017 |
14 | 37c759bc793d |
15 | 1a0641dbcea1 |
hex | d204aa48343 |
14432342410051 has 2 divisors, whose sum is σ = 14432342410052. Its totient is φ = 14432342410050.
The previous prime is 14432342410039. The next prime is 14432342410061. The reversal of 14432342410051 is 15001424323441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14432342410051 - 227 = 14432208192323 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14432342409989 and 14432342410016.
It is not a weakly prime, because it can be changed into another prime (14432342410001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7216171205025 + 7216171205026.
It is an arithmetic number, because the mean of its divisors is an integer number (7216171205026).
Almost surely, 214432342410051 is an apocalyptic number.
14432342410051 is a deficient number, since it is larger than the sum of its proper divisors (1).
14432342410051 is an equidigital number, since it uses as much as digits as its factorization.
14432342410051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46080, while the sum is 34.
Adding to 14432342410051 its reverse (15001424323441), we get a palindrome (29433766733492).
The spelling of 14432342410051 in words is "fourteen trillion, four hundred thirty-two billion, three hundred forty-two million, four hundred ten thousand, fifty-one".
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