Base | Representation |
---|---|
bin | 100000110100010010000110… |
… | …110101111110101011111011 |
3 | 200221000211211210011020100101 |
4 | 200310102012311332223323 |
5 | 122404202020341441443 |
6 | 1230544235552420231 |
7 | 42254344312104433 |
oct | 4064220665765373 |
9 | 627024753136311 |
10 | 144330343312123 |
11 | 41a9617812a671 |
12 | 1423022bb47677 |
13 | 626c3a6883b97 |
14 | 278d8a96232c3 |
15 | 11a456b99684d |
hex | 834486d7eafb |
144330343312123 has 4 divisors (see below), whose sum is σ = 144525648242920. Its totient is φ = 144135038381328.
The previous prime is 144330343312073. The next prime is 144330343312159. The reversal of 144330343312123 is 321213343033441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 144330343312123 - 213 = 144330343303931 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (144330344312123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97652464290 + ... + 97652465767.
It is an arithmetic number, because the mean of its divisors is an integer number (36131412060730).
Almost surely, 2144330343312123 is an apocalyptic number.
144330343312123 is a deficient number, since it is larger than the sum of its proper divisors (195304930797).
144330343312123 is an equidigital number, since it uses as much as digits as its factorization.
144330343312123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 195304930796.
The product of its (nonzero) digits is 186624, while the sum is 37.
Adding to 144330343312123 its reverse (321213343033441), we get a palindrome (465543686345564).
The spelling of 144330343312123 in words is "one hundred forty-four trillion, three hundred thirty billion, three hundred forty-three million, three hundred twelve thousand, one hundred twenty-three".
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