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1443317340649 is a prime number
BaseRepresentation
bin10101000000001100011…
…010101101100111101001
312002222110021012200211211
4111000030122231213221
5142121403214400044
63023014551353121
7206163514654642
oct25001432554751
95088407180754
101443317340649
11507120014478
121b38840827a1
13a61480305a2
144dbdd5c86c9
1527825ec2634
hex1500c6ad9e9

1443317340649 has 2 divisors, whose sum is σ = 1443317340650. Its totient is φ = 1443317340648.

The previous prime is 1443317340631. The next prime is 1443317340691. The reversal of 1443317340649 is 9460437133441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1163971265625 + 279346075024 = 1078875^2 + 528532^2 .

It is a cyclic number.

It is not a de Polignac number, because 1443317340649 - 215 = 1443317307881 is a prime.

It is not a weakly prime, because it can be changed into another prime (1443317380649) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 721658670324 + 721658670325.

It is an arithmetic number, because the mean of its divisors is an integer number (721658670325).

Almost surely, 21443317340649 is an apocalyptic number.

It is an amenable number.

1443317340649 is a deficient number, since it is larger than the sum of its proper divisors (1).

1443317340649 is an equidigital number, since it uses as much as digits as its factorization.

1443317340649 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2612736, while the sum is 49.

The spelling of 1443317340649 in words is "one trillion, four hundred forty-three billion, three hundred seventeen million, three hundred forty thousand, six hundred forty-nine".