Base | Representation |
---|---|
bin | 11010111000100100… |
… | …10011000100001001 |
3 | 1101020212121122121101 |
4 | 31130102103010021 |
5 | 214024344434231 |
6 | 10344105341401 |
7 | 1020445124260 |
oct | 153422230411 |
9 | 41225548541 |
10 | 14433202441 |
11 | 6137191689 |
12 | 2969797861 |
13 | 14902a6c98 |
14 | 9acc415d7 |
15 | 5971a4661 |
hex | 35c493109 |
14433202441 has 4 divisors (see below), whose sum is σ = 16495088512. Its totient is φ = 12371316372.
The previous prime is 14433202429. The next prime is 14433202447. The reversal of 14433202441 is 14420233441.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14433202441 - 211 = 14433200393 is a prime.
It is a super-4 number, since 4×144332024414 (a number of 42 digits) contains 4444 as substring.
It is not an unprimeable number, because it can be changed into a prime (14433202447) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1030943025 + ... + 1030943038.
It is an arithmetic number, because the mean of its divisors is an integer number (4123772128).
Almost surely, 214433202441 is an apocalyptic number.
It is an amenable number.
14433202441 is a deficient number, since it is larger than the sum of its proper divisors (2061886071).
14433202441 is an equidigital number, since it uses as much as digits as its factorization.
14433202441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2061886070.
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 14433202441 its reverse (14420233441), we get a palindrome (28853435882).
The spelling of 14433202441 in words is "fourteen billion, four hundred thirty-three million, two hundred two thousand, four hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •