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144335041 is a prime number
BaseRepresentation
bin10001001101001…
…10000011000001
3101001120222110021
420212212003001
5243422210131
622153333441
73401553604
oct1046460301
9331528407
10144335041
1174523064
1240407281
1323b97566
141525233b
15ca10e11
hex89a60c1

144335041 has 2 divisors, whose sum is σ = 144335042. Its totient is φ = 144335040.

The previous prime is 144335027. The next prime is 144335099. The reversal of 144335041 is 140533441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111513600 + 32821441 = 10560^2 + 5729^2 .

It is a cyclic number.

It is not a de Polignac number, because 144335041 - 213 = 144326849 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 144334997 and 144335015.

It is not a weakly prime, because it can be changed into another prime (144335341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72167520 + 72167521.

It is an arithmetic number, because the mean of its divisors is an integer number (72167521).

Almost surely, 2144335041 is an apocalyptic number.

It is an amenable number.

144335041 is a deficient number, since it is larger than the sum of its proper divisors (1).

144335041 is an equidigital number, since it uses as much as digits as its factorization.

144335041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 25.

The square root of 144335041 is about 12013.9519309842. The cubic root of 144335041 is about 524.5544713016.

Adding to 144335041 its reverse (140533441), we get a palindrome (284868482).

The spelling of 144335041 in words is "one hundred forty-four million, three hundred thirty-five thousand, forty-one".