14434023302051 has 2 divisors, whose sum is σ = 14434023302052. Its totient is φ = 14434023302050.

The previous prime is 14434023302003. The next prime is 14434023302057. The reversal of 14434023302051 is 15020332043441.

14434023302051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14434023302051 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14434023301999 and 14434023302017.

It is not a weakly prime, because it can be changed into another prime (14434023302057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7217011651025 + 7217011651026.

It is an arithmetic number, because the mean of its divisors is an integer number (7217011651026).

Almost surely, 2^{14434023302051} is an apocalyptic number.

14434023302051 is a deficient number, since it is larger than the sum of its proper divisors (1).

14434023302051 is an equidigital number, since it uses as much as digits as its factorization.

14434023302051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34560, while the sum is 32.

Adding to 14434023302051 its reverse (15020332043441), we get a palindrome (29454355345492).

The spelling of 14434023302051 in words is "fourteen trillion, four hundred thirty-four billion, twenty-three million, three hundred two thousand, fifty-one".