14434113242033 has 2 divisors, whose sum is σ = 14434113242034. Its totient is φ = 14434113242032.

The previous prime is 14434113241981. The next prime is 14434113242039. The reversal of 14434113242033 is 33024231143441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13361598243904 + 1072514998129 = 3655352^2 + 1035623^2 .

It is a cyclic number.

It is not a de Polignac number, because 14434113242033 - 2⁸ = 14434113241777 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14434113241984 and 14434113242002.

It is not a weakly prime, because it can be changed into another prime (14434113242039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7217056621016 + 7217056621017.

It is an arithmetic number, because the mean of its divisors is an integer number (7217056621017).

Almost surely, 2^{14434113242033} is an apocalyptic number.

It is an amenable number.

14434113242033 is a deficient number, since it is larger than the sum of its proper divisors (1).

14434113242033 is an equidigital number, since it uses as much as digits as its factorization.

14434113242033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 14434113242033 its reverse (33024231143441), we get a palindrome (47458344385474).

The spelling of 14434113242033 in words is "fourteen trillion, four hundred thirty-four billion, one hundred thirteen million, two hundred forty-two thousand, thirty-three".