Base | Representation |
---|---|
bin | 11010111001011001… |
… | …01100001111100010 |
3 | 1101021100122011111221 |
4 | 31130230230033202 |
5 | 214033132340224 |
6 | 10344513525254 |
7 | 1020561002023 |
oct | 153454541742 |
9 | 41240564457 |
10 | 14440121314 |
11 | 6140087963 |
12 | 296bb7382a |
13 | 149185a2a8 |
14 | 9adb22c4a |
15 | 597abe6e4 |
hex | 35cb2c3e2 |
14440121314 has 4 divisors (see below), whose sum is σ = 21660181974. Its totient is φ = 7220060656.
The previous prime is 14440121287. The next prime is 14440121323. The reversal of 14440121314 is 41312104441.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41312104441 = 25849 ⋅1598209.
It can be written as a sum of positive squares in only one way, i.e., 10535996025 + 3904125289 = 102645^2 + 62483^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3610030327 + ... + 3610030330.
Almost surely, 214440121314 is an apocalyptic number.
14440121314 is a deficient number, since it is larger than the sum of its proper divisors (7220060660).
14440121314 is an equidigital number, since it uses as much as digits as its factorization.
14440121314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7220060659.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 14440121314 its reverse (41312104441), we get a palindrome (55752225755).
The spelling of 14440121314 in words is "fourteen billion, four hundred forty million, one hundred twenty-one thousand, three hundred fourteen".
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