14441120041433 has 2 divisors, whose sum is σ = 14441120041434. Its totient is φ = 14441120041432.

The previous prime is 14441120041427. The next prime is 14441120041441. The reversal of 14441120041433 is 33414002114441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13780220957584 + 660899083849 = 3712172^2 + 812957^2 .

It is a cyclic number.

It is not a de Polignac number, because 14441120041433 - 2¹⁴ = 14441120025049 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14441120041433.

It is not a weakly prime, because it can be changed into another prime (14441120041133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7220560020716 + 7220560020717.

It is an arithmetic number, because the mean of its divisors is an integer number (7220560020717).

Almost surely, 2^{14441120041433} is an apocalyptic number.

It is an amenable number.

14441120041433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14441120041433 is an equidigital number, since it uses as much as digits as its factorization.

14441120041433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18432, while the sum is 32.

Adding to 14441120041433 its reverse (33414002114441), we get a palindrome (47855122155874).

The spelling of 14441120041433 in words is "fourteen trillion, four hundred forty-one billion, one hundred twenty million, forty-one thousand, four hundred thirty-three".