Base | Representation |
---|---|
bin | 11010111001100010… |
… | …01111001110110010 |
3 | 1101021102212201110221 |
4 | 31130301033032302 |
5 | 214033434010302 |
6 | 10344555243254 |
7 | 1020604064641 |
oct | 153461171662 |
9 | 41242781427 |
10 | 14441313202 |
11 | 6140821398 |
12 | 297044952a |
13 | 1491b86954 |
14 | 9add53358 |
15 | 597c57937 |
hex | 35cc4f3b2 |
14441313202 has 4 divisors (see below), whose sum is σ = 21661969806. Its totient is φ = 7220656600.
The previous prime is 14441313091. The next prime is 14441313269. The reversal of 14441313202 is 20231314441.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 7828533441 + 6612779761 = 88479^2 + 81319^2 .
It is a super-3 number, since 3×144413132023 (a number of 31 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3610328299 + ... + 3610328302.
Almost surely, 214441313202 is an apocalyptic number.
14441313202 is a deficient number, since it is larger than the sum of its proper divisors (7220656604).
14441313202 is an equidigital number, since it uses as much as digits as its factorization.
14441313202 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7220656603.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 14441313202 its reverse (20231314441), we get a palindrome (34672627643).
The spelling of 14441313202 in words is "fourteen billion, four hundred forty-one million, three hundred thirteen thousand, two hundred two".
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