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144423015131 is a prime number
BaseRepresentation
bin1000011010000001001…
…0000101001011011011
3111210210002101022212102
42012200102011023123
54331234242441011
6150202542234015
713301636242103
oct2064022051333
9453702338772
10144423015131
115628203294a
1223ba6b8590b
1310808022905
146dc0c18203
153b541a473b
hex21a04852db

144423015131 has 2 divisors, whose sum is σ = 144423015132. Its totient is φ = 144423015130.

The previous prime is 144423015119. The next prime is 144423015157. The reversal of 144423015131 is 131510324441.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 144423015131 - 222 = 144418820827 is a prime.

It is a super-2 number, since 2×1444230151312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 144423015094 and 144423015103.

It is not a weakly prime, because it can be changed into another prime (144423015431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72211507565 + 72211507566.

It is an arithmetic number, because the mean of its divisors is an integer number (72211507566).

Almost surely, 2144423015131 is an apocalyptic number.

144423015131 is a deficient number, since it is larger than the sum of its proper divisors (1).

144423015131 is an equidigital number, since it uses as much as digits as its factorization.

144423015131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 144423015131 its reverse (131510324441), we get a palindrome (275933339572).

The spelling of 144423015131 in words is "one hundred forty-four billion, four hundred twenty-three million, fifteen thousand, one hundred thirty-one".