Base | Representation |
---|---|
bin | 1101001000101001110110… |
… | …0110110010100000110001 |
3 | 1220010200011102000111201211 |
4 | 3102022131212302200301 |
5 | 3343110340001143213 |
6 | 50414413454400121 |
7 | 3020265154353415 |
oct | 322123546624061 |
9 | 56120142014654 |
10 | 14442324240433 |
11 | 4668a56583291 |
12 | 1753029200041 |
13 | 809ba002622b |
14 | 37d02577ad45 |
15 | 1a0a2838c53d |
hex | d229d9b2831 |
14442324240433 has 2 divisors, whose sum is σ = 14442324240434. Its totient is φ = 14442324240432.
The previous prime is 14442324240367. The next prime is 14442324240451. The reversal of 14442324240433 is 33404242324441.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8102972151184 + 6339352089249 = 2846572^2 + 2517807^2 .
It is a cyclic number.
It is not a de Polignac number, because 14442324240433 - 241 = 12243300984881 is a prime.
It is not a weakly prime, because it can be changed into another prime (14442324240473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7221162120216 + 7221162120217.
It is an arithmetic number, because the mean of its divisors is an integer number (7221162120217).
Almost surely, 214442324240433 is an apocalyptic number.
It is an amenable number.
14442324240433 is a deficient number, since it is larger than the sum of its proper divisors (1).
14442324240433 is an equidigital number, since it uses as much as digits as its factorization.
14442324240433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 884736, while the sum is 40.
Adding to 14442324240433 its reverse (33404242324441), we get a palindrome (47846566564874).
The spelling of 14442324240433 in words is "fourteen trillion, four hundred forty-two billion, three hundred twenty-four million, two hundred forty thousand, four hundred thirty-three".
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