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144431254049 is a prime number
BaseRepresentation
bin1000011010000011000…
…1100000101000100001
3111210210122212220112112
42012200301200220201
54331243400112144
6150203435005105
713302066255215
oct2064061405041
9453718786475
10144431254049
115628674a975
1223ba9899795
1310809948a04
146dc1d60945
153b54c8099e
hex21a0c60a21

144431254049 has 2 divisors, whose sum is σ = 144431254050. Its totient is φ = 144431254048.

The previous prime is 144431254013. The next prime is 144431254127. The reversal of 144431254049 is 940452134441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97090197649 + 47341056400 = 311593^2 + 217580^2 .

It is a cyclic number.

It is not a de Polignac number, because 144431254049 - 212 = 144431249953 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 144431253997 and 144431254015.

It is not a weakly prime, because it can be changed into another prime (144431254249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72215627024 + 72215627025.

It is an arithmetic number, because the mean of its divisors is an integer number (72215627025).

Almost surely, 2144431254049 is an apocalyptic number.

It is an amenable number.

144431254049 is a deficient number, since it is larger than the sum of its proper divisors (1).

144431254049 is an equidigital number, since it uses as much as digits as its factorization.

144431254049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 276480, while the sum is 41.

The spelling of 144431254049 in words is "one hundred forty-four billion, four hundred thirty-one million, two hundred fifty-four thousand, forty-nine".