Base | Representation |
---|---|
bin | 1101001000101101000000… |
… | …0110100011111001110011 |
3 | 1220010202100110011012100022 |
4 | 3102023100012203321303 |
5 | 3343114103341230003 |
6 | 50415033520514055 |
7 | 3020325152351021 |
oct | 322132006437163 |
9 | 56122313135308 |
10 | 14443171430003 |
11 | 4669350815358 |
12 | 1753224a7b92b |
13 | 809ca66bc234 |
14 | 37d0a60ab711 |
15 | 1a0a77936738 |
hex | d22d01a3e73 |
14443171430003 has 4 divisors (see below), whose sum is σ = 14531779843848. Its totient is φ = 14354563016160.
The previous prime is 14443171429979. The next prime is 14443171430029. The reversal of 14443171430003 is 30003417134441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14443171430003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14443171430053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44304206678 + ... + 44304207003.
It is an arithmetic number, because the mean of its divisors is an integer number (3632944960962).
Almost surely, 214443171430003 is an apocalyptic number.
14443171430003 is a deficient number, since it is larger than the sum of its proper divisors (88608413845).
14443171430003 is an equidigital number, since it uses as much as digits as its factorization.
14443171430003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 88608413844.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 14443171430003 its reverse (30003417134441), we get a palindrome (44446588564444).
The spelling of 14443171430003 in words is "fourteen trillion, four hundred forty-three billion, one hundred seventy-one million, four hundred thirty thousand, three".
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