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1444340142353 is a prime number
BaseRepresentation
bin10101000001001001011…
…000011001000100010001
312010002002112210102000102
4111001021120121010101
5142131002034023403
63023304245502145
7206231044434053
oct25011130310421
95102075712012
101444340142353
115075a53a1539
121b3b0a711955
13a627bbc21b4
144dc9938d8d3
1527885ba9b88
hex15049619111

1444340142353 has 2 divisors, whose sum is σ = 1444340142354. Its totient is φ = 1444340142352.

The previous prime is 1444340142317. The next prime is 1444340142361. The reversal of 1444340142353 is 3532410434441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1181803803664 + 262536338689 = 1087108^2 + 512383^2 .

It is a cyclic number.

It is not a de Polignac number, because 1444340142353 - 220 = 1444339093777 is a prime.

It is a super-2 number, since 2×14443401423532 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1444340142383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 722170071176 + 722170071177.

It is an arithmetic number, because the mean of its divisors is an integer number (722170071177).

Almost surely, 21444340142353 is an apocalyptic number.

It is an amenable number.

1444340142353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1444340142353 is an equidigital number, since it uses as much as digits as its factorization.

1444340142353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 276480, while the sum is 38.

Adding to 1444340142353 its reverse (3532410434441), we get a palindrome (4976750576794).

The spelling of 1444340142353 in words is "one trillion, four hundred forty-four billion, three hundred forty million, one hundred forty-two thousand, three hundred fifty-three".