Base | Representation |
---|---|
bin | 10101000001001001011… |
… | …000011001000100010001 |
3 | 12010002002112210102000102 |
4 | 111001021120121010101 |
5 | 142131002034023403 |
6 | 3023304245502145 |
7 | 206231044434053 |
oct | 25011130310421 |
9 | 5102075712012 |
10 | 1444340142353 |
11 | 5075a53a1539 |
12 | 1b3b0a711955 |
13 | a627bbc21b4 |
14 | 4dc9938d8d3 |
15 | 27885ba9b88 |
hex | 15049619111 |
1444340142353 has 2 divisors, whose sum is σ = 1444340142354. Its totient is φ = 1444340142352.
The previous prime is 1444340142317. The next prime is 1444340142361. The reversal of 1444340142353 is 3532410434441.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1181803803664 + 262536338689 = 1087108^2 + 512383^2 .
It is a cyclic number.
It is not a de Polignac number, because 1444340142353 - 220 = 1444339093777 is a prime.
It is a super-2 number, since 2×14443401423532 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1444340142383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 722170071176 + 722170071177.
It is an arithmetic number, because the mean of its divisors is an integer number (722170071177).
Almost surely, 21444340142353 is an apocalyptic number.
It is an amenable number.
1444340142353 is a deficient number, since it is larger than the sum of its proper divisors (1).
1444340142353 is an equidigital number, since it uses as much as digits as its factorization.
1444340142353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 276480, while the sum is 38.
Adding to 1444340142353 its reverse (3532410434441), we get a palindrome (4976750576794).
The spelling of 1444340142353 in words is "one trillion, four hundred forty-four billion, three hundred forty million, one hundred forty-two thousand, three hundred fifty-three".
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