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1444344183449 is a prime number
BaseRepresentation
bin10101000001001001100…
…111110011101010011001
312010002002211101201100122
4111001021213303222121
5142131004102332244
63023304512243025
7206231123664506
oct25011147635231
95102084351318
101444344183449
115075a7701692
121b3b0bb40475
13a627c9a868b
144dc99b224ad
15278862071ee
hex150499f3a99

1444344183449 has 2 divisors, whose sum is σ = 1444344183450. Its totient is φ = 1444344183448.

The previous prime is 1444344183383. The next prime is 1444344183463. The reversal of 1444344183449 is 9443814434441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1083071059849 + 361273123600 = 1040707^2 + 601060^2 .

It is a cyclic number.

It is not a de Polignac number, because 1444344183449 - 212 = 1444344179353 is a prime.

It is a super-2 number, since 2×14443441834492 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1444344183449.

It is not a weakly prime, because it can be changed into another prime (1444344183479) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 722172091724 + 722172091725.

It is an arithmetic number, because the mean of its divisors is an integer number (722172091725).

Almost surely, 21444344183449 is an apocalyptic number.

It is an amenable number.

1444344183449 is a deficient number, since it is larger than the sum of its proper divisors (1).

1444344183449 is an equidigital number, since it uses as much as digits as its factorization.

1444344183449 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10616832, while the sum is 53.

The spelling of 1444344183449 in words is "one trillion, four hundred forty-four billion, three hundred forty-four million, one hundred eighty-three thousand, four hundred forty-nine".