14443650433243 has 2 divisors, whose sum is σ = 14443650433244. Its totient is φ = 14443650433242.

The previous prime is 14443650433237. The next prime is 14443650433291. The reversal of 14443650433243 is 34233405634441.

14443650433243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14443650433243 - 2¹³ = 14443650425051 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14443650433193 and 14443650433202.

It is not a weakly prime, because it can be changed into another prime (14443650533243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7221825216621 + 7221825216622.

It is an arithmetic number, because the mean of its divisors is an integer number (7221825216622).

Almost surely, 2^{14443650433243} is an apocalyptic number.

14443650433243 is a deficient number, since it is larger than the sum of its proper divisors (1).

14443650433243 is an equidigital number, since it uses as much as digits as its factorization.

14443650433243 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4976640, while the sum is 46.

The spelling of 14443650433243 in words is "fourteen trillion, four hundred forty-three billion, six hundred fifty million, four hundred thirty-three thousand, two hundred forty-three".