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144443103131 is a prime number
BaseRepresentation
bin1000011010000101111…
…0101101011110011011
3111210211111011220102102
42012201132231132123
54331304413300011
6150204540554015
713302302055515
oct2064136553633
9453744156372
10144443103131
11562924032a8
1223bb185290b
131080c2370c2
146dc3766bb5
153b55d2173b
hex21a17ad79b

144443103131 has 2 divisors, whose sum is σ = 144443103132. Its totient is φ = 144443103130.

The previous prime is 144443103121. The next prime is 144443103143. The reversal of 144443103131 is 131301344441.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 144443103131 - 214 = 144443086747 is a prime.

It is a super-2 number, since 2×1444431031312 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 144443103094 and 144443103103.

It is not a weakly prime, because it can be changed into another prime (144443103121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72221551565 + 72221551566.

It is an arithmetic number, because the mean of its divisors is an integer number (72221551566).

Almost surely, 2144443103131 is an apocalyptic number.

144443103131 is a deficient number, since it is larger than the sum of its proper divisors (1).

144443103131 is an equidigital number, since it uses as much as digits as its factorization.

144443103131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 144443103131 its reverse (131301344441), we get a palindrome (275744447572).

The spelling of 144443103131 in words is "one hundred forty-four billion, four hundred forty-three million, one hundred three thousand, one hundred thirty-one".