Base | Representation |
---|---|
bin | 1101001001000110101001… |
… | …0111111001001111011011 |
3 | 1220011102010011010002221211 |
4 | 3102101222113321033123 |
5 | 3343222202441214121 |
6 | 50422132523443551 |
7 | 3020660552534356 |
oct | 322215227711733 |
9 | 56142104102854 |
10 | 14450054632411 |
11 | 4671263145192 |
12 | 17546260865b7 |
13 | 80a83274ca78 |
14 | 37d55a30329d |
15 | 1a0d2bd7dce1 |
hex | d246a5f93db |
14450054632411 has 2 divisors, whose sum is σ = 14450054632412. Its totient is φ = 14450054632410.
The previous prime is 14450054632397. The next prime is 14450054632417. The reversal of 14450054632411 is 11423645005441.
It is a strong prime.
It is an emirp because it is prime and its reverse (11423645005441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14450054632411 - 25 = 14450054632379 is a prime.
It is not a weakly prime, because it can be changed into another prime (14450054632417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7225027316205 + 7225027316206.
It is an arithmetic number, because the mean of its divisors is an integer number (7225027316206).
Almost surely, 214450054632411 is an apocalyptic number.
14450054632411 is a deficient number, since it is larger than the sum of its proper divisors (1).
14450054632411 is an equidigital number, since it uses as much as digits as its factorization.
14450054632411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 230400, while the sum is 40.
Adding to 14450054632411 its reverse (11423645005441), we get a palindrome (25873699637852).
The spelling of 14450054632411 in words is "fourteen trillion, four hundred fifty billion, fifty-four million, six hundred thirty-two thousand, four hundred eleven".
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