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14500103234443 is a prime number
BaseRepresentation
bin1101001100000001000110…
…0000001010001110001011
31220100012022010101112000221
43103000101200022032023
53400032202412000233
650501131103010511
73024412034613121
oct323002140121613
956305263345027
1014500103234443
114690506293702
121762273299a37
1381247a5a8798
14381b47285911
151a22aab2442d
hexd301180a38b

14500103234443 has 2 divisors, whose sum is σ = 14500103234444. Its totient is φ = 14500103234442.

The previous prime is 14500103234431. The next prime is 14500103234467. The reversal of 14500103234443 is 34443230100541.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14500103234443 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14500103234399 and 14500103234408.

It is not a weakly prime, because it can be changed into another prime (14500103234483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7250051617221 + 7250051617222.

It is an arithmetic number, because the mean of its divisors is an integer number (7250051617222).

Almost surely, 214500103234443 is an apocalyptic number.

14500103234443 is a deficient number, since it is larger than the sum of its proper divisors (1).

14500103234443 is an equidigital number, since it uses as much as digits as its factorization.

14500103234443 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69120, while the sum is 34.

Adding to 14500103234443 its reverse (34443230100541), we get a palindrome (48943333334984).

The spelling of 14500103234443 in words is "fourteen trillion, five hundred billion, one hundred three million, two hundred thirty-four thousand, four hundred forty-three".