Search a number
-
+
14500113 = 34833371
BaseRepresentation
bin110111010100…
…000100010001
31000021200102020
4313110010101
512203000423
61234442053
7234151245
oct67240421
930250366
1014500113
118204171
124a33329
133008c64
141cd6425
1514164e3
hexdd4111

14500113 has 4 divisors (see below), whose sum is σ = 19333488. Its totient is φ = 9666740.

The previous prime is 14500103. The next prime is 14500121. The reversal of 14500113 is 31100541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14500113 - 25 = 14500081 is a prime.

It is a nialpdrome in base 16.

It is a junction number, because it is equal to n+sod(n) for n = 14500092 and 14500101.

It is not an unprimeable number, because it can be changed into a prime (14500103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2416683 + ... + 2416688.

It is an arithmetic number, because the mean of its divisors is an integer number (4833372).

Almost surely, 214500113 is an apocalyptic number.

It is an amenable number.

14500113 is a deficient number, since it is larger than the sum of its proper divisors (4833375).

14500113 is an equidigital number, since it uses as much as digits as its factorization.

14500113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4833374.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 14500113 is about 3807.9013905300. The cubic root of 14500113 is about 243.8505815013.

Adding to 14500113 its reverse (31100541), we get a palindrome (45600654).

The spelling of 14500113 in words is "fourteen million, five hundred thousand, one hundred thirteen".

Divisors: 1 3 4833371 14500113