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145001144460041 is a prime number
BaseRepresentation
bin100000111110000010110101…
…101101010010001100001001
3201000101222022001212021001022
4200332002311231102030021
5123001144320440210131
61232220334533202225
742353662350556352
oct4076026555221411
9630358261767038
10145001144460041
114222470496a551
121431a239a90375
1362ba71a92124c
1427b4142a66d29
1511b6c2c42737b
hex83e0b5b52309

145001144460041 has 2 divisors, whose sum is σ = 145001144460042. Its totient is φ = 145001144460040.

The previous prime is 145001144460013. The next prime is 145001144460119. The reversal of 145001144460041 is 140064441100541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 144928395581641 + 72748878400 = 12038621^2 + 269720^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-145001144460041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 145001144459983 and 145001144460010.

It is not a weakly prime, because it can be changed into another prime (145001144465041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72500572230020 + 72500572230021.

It is an arithmetic number, because the mean of its divisors is an integer number (72500572230021).

Almost surely, 2145001144460041 is an apocalyptic number.

It is an amenable number.

145001144460041 is a deficient number, since it is larger than the sum of its proper divisors (1).

145001144460041 is an equidigital number, since it uses as much as digits as its factorization.

145001144460041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30720, while the sum is 35.

Adding to 145001144460041 its reverse (140064441100541), we get a palindrome (285065585560582).

The spelling of 145001144460041 in words is "one hundred forty-five trillion, one billion, one hundred forty-four million, four hundred sixty thousand, forty-one".