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145002623330531 is a prime number
BaseRepresentation
bin100000111110000100001101…
…110110101110100011100011
3201000102010010010121122222102
4200332010031312232203203
5123001210333033034111
61232221141402401015
742354044116012211
oct4076041566564343
9630363103548872
10145002623330531
11422252a372886a
121431a59120016b
1362ba8c5125c45
1427b4243229cb1
1511b6cb719b13b
hex83e10ddae8e3

145002623330531 has 2 divisors, whose sum is σ = 145002623330532. Its totient is φ = 145002623330530.

The previous prime is 145002623330527. The next prime is 145002623330561. The reversal of 145002623330531 is 135033326200541.

145002623330531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (135033326200541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 145002623330531 - 22 = 145002623330527 is a prime.

It is a super-3 number, since 3×1450026233305313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (145002623330561) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72501311665265 + 72501311665266.

It is an arithmetic number, because the mean of its divisors is an integer number (72501311665266).

Almost surely, 2145002623330531 is an apocalyptic number.

145002623330531 is a deficient number, since it is larger than the sum of its proper divisors (1).

145002623330531 is an equidigital number, since it uses as much as digits as its factorization.

145002623330531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 194400, while the sum is 38.

The spelling of 145002623330531 in words is "one hundred forty-five trillion, two billion, six hundred twenty-three million, three hundred thirty thousand, five hundred thirty-one".