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145011213265187 is a prime number
BaseRepresentation
bin100000111110001100001101…
…110110101110100100100011
3201000102221021210002120002102
4200332030031312232210203
5123001330431043441222
61232225122014441015
742354500022160403
oct4076141566564443
9630387253076072
10145011213265187
1142228a014a9915
1214320189b0316b
1362bb66394c409
1427b4819dba803
1511b711b376d92
hex83e30ddae923

145011213265187 has 2 divisors, whose sum is σ = 145011213265188. Its totient is φ = 145011213265186.

The previous prime is 145011213265099. The next prime is 145011213265241. The reversal of 145011213265187 is 781562312110541.

145011213265187 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 145011213265187 - 226 = 145011146156323 is a prime.

It is a super-2 number, since 2×1450112132651872 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (145011213265687) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72505606632593 + 72505606632594.

It is an arithmetic number, because the mean of its divisors is an integer number (72505606632594).

Almost surely, 2145011213265187 is an apocalyptic number.

145011213265187 is a deficient number, since it is larger than the sum of its proper divisors (1).

145011213265187 is an equidigital number, since it uses as much as digits as its factorization.

145011213265187 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 403200, while the sum is 47.

The spelling of 145011213265187 in words is "one hundred forty-five trillion, eleven billion, two hundred thirteen million, two hundred sixty-five thousand, one hundred eighty-seven".