Base | Representation |
---|---|
bin | 1000011100001101011… |
… | …0111111110111010001 |
3 | 111212022002201210110021 |
4 | 2013003112333313101 |
5 | 4333440421203031 |
6 | 150341203503441 |
7 | 13322343316561 |
oct | 2070326776721 |
9 | 455262653407 |
10 | 145011506641 |
11 | 56554240271 |
12 | 24130087b81 |
13 | 1089cc1c141 |
14 | 7039046da1 |
15 | 3b8ab9c511 |
hex | 21c35bfdd1 |
145011506641 has 2 divisors, whose sum is σ = 145011506642. Its totient is φ = 145011506640.
The previous prime is 145011506609. The next prime is 145011506657. The reversal of 145011506641 is 146605110541.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 74824131600 + 70187375041 = 273540^2 + 264929^2 .
It is a cyclic number.
It is not a de Polignac number, because 145011506641 - 25 = 145011506609 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 145011506597 and 145011506606.
It is not a weakly prime, because it can be changed into another prime (145011506681) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72505753320 + 72505753321.
It is an arithmetic number, because the mean of its divisors is an integer number (72505753321).
Almost surely, 2145011506641 is an apocalyptic number.
It is an amenable number.
145011506641 is a deficient number, since it is larger than the sum of its proper divisors (1).
145011506641 is an equidigital number, since it uses as much as digits as its factorization.
145011506641 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 34.
The spelling of 145011506641 in words is "one hundred forty-five billion, eleven million, five hundred six thousand, six hundred forty-one".
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