Base | Representation |
---|---|
bin | 10101000110100010001… |
… | …100011110111001010011 |
3 | 12010122000201022202100222 |
4 | 111012202030132321103 |
5 | 142224324020110034 |
6 | 3030102302503255 |
7 | 206524311324554 |
oct | 25064214367123 |
9 | 5118021282328 |
10 | 1450125160019 |
11 | 509aa3936978 |
12 | 1b5063b94b2b |
13 | a6991589383 |
14 | 502877da32b |
15 | 27ac39c912e |
hex | 151a231ee53 |
1450125160019 has 2 divisors, whose sum is σ = 1450125160020. Its totient is φ = 1450125160018.
The previous prime is 1450125160009. The next prime is 1450125160079. The reversal of 1450125160019 is 9100615210541.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1450125160019 - 212 = 1450125155923 is a prime.
It is a super-3 number, since 3×14501251600193 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (1450125160009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 725062580009 + 725062580010.
It is an arithmetic number, because the mean of its divisors is an integer number (725062580010).
Almost surely, 21450125160019 is an apocalyptic number.
1450125160019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1450125160019 is an equidigital number, since it uses as much as digits as its factorization.
1450125160019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 35.
The spelling of 1450125160019 in words is "one trillion, four hundred fifty billion, one hundred twenty-five million, one hundred sixty thousand, nineteen".
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