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1450213113137 is a prime number
BaseRepresentation
bin10101000110100111011…
…011111111110100110001
312010122020211211020100212
4111012213123333310301
5142230014024110022
63030115123553505
7206526430033625
oct25064733776461
95118224736325
101450213113137
1150a03954a3a8
121b508952b895
13a69a6872739
1450295373185
1527acb59e3e2
hex151a76ffd31

1450213113137 has 2 divisors, whose sum is σ = 1450213113138. Its totient is φ = 1450213113136.

The previous prime is 1450213113131. The next prime is 1450213113211. The reversal of 1450213113137 is 7313113120541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 769718456896 + 680494656241 = 877336^2 + 824921^2 .

It is a cyclic number.

It is not a de Polignac number, because 1450213113137 - 224 = 1450196335921 is a prime.

It is not a weakly prime, because it can be changed into another prime (1450213113131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 725106556568 + 725106556569.

It is an arithmetic number, because the mean of its divisors is an integer number (725106556569).

Almost surely, 21450213113137 is an apocalyptic number.

It is an amenable number.

1450213113137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1450213113137 is an equidigital number, since it uses as much as digits as its factorization.

1450213113137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7560, while the sum is 32.

Adding to 1450213113137 its reverse (7313113120541), we get a palindrome (8763326233678).

The spelling of 1450213113137 in words is "one trillion, four hundred fifty billion, two hundred thirteen million, one hundred thirteen thousand, one hundred thirty-seven".