145024561113 has 4 divisors (see below), whose sum is σ = 193366081488. Its totient is φ = 96683040740.

The previous prime is 145024561109. The next prime is 145024561207. The reversal of 145024561113 is 311165420541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 145024561113 - 2² = 145024561109 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (145024561313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24170760183 + ... + 24170760188.

It is an arithmetic number, because the mean of its divisors is an integer number (48341520372).

Almost surely, 2^145024561113 is an apocalyptic number.

It is an amenable number.

145024561113 is a deficient number, since it is larger than the sum of its proper divisors (48341520375).

145024561113 is an equidigital number, since it uses as much as digits as its factorization.

145024561113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48341520374.

The product of its (nonzero) digits is 14400, while the sum is 33.

Adding to 145024561113 its reverse (311165420541), we get a palindrome (456189981654).

The spelling of 145024561113 in words is "one hundred forty-five billion, twenty-four million, five hundred sixty-one thousand, one hundred thirteen".