145024631331 has 4 divisors (see below), whose sum is σ = 193366175112. Its totient is φ = 96683087552.

The previous prime is 145024631299. The next prime is 145024631357. The reversal of 145024631331 is 133136420541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 145024631331 - 2⁵ = 145024631299 is a prime.

It is a super-2 number, since 2×145024631331² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 145024631292 and 145024631301.

It is not an unprimeable number, because it can be changed into a prime (145024638331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24170771886 + ... + 24170771891.

It is an arithmetic number, because the mean of its divisors is an integer number (48341543778).

Almost surely, 2^145024631331 is an apocalyptic number.

145024631331 is a deficient number, since it is larger than the sum of its proper divisors (48341543781).

145024631331 is an equidigital number, since it uses as much as digits as its factorization.

145024631331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48341543780.

The product of its (nonzero) digits is 25920, while the sum is 33.

The spelling of 145024631331 in words is "one hundred forty-five billion, twenty-four million, six hundred thirty-one thousand, three hundred thirty-one".