Base | Representation |
---|---|
bin | 1101001100001100011000… |
… | …0000001001110000001011 |
3 | 1220100111010011122100212200 |
4 | 3103003012000021300023 |
5 | 3400104403132120021 |
6 | 50502351401411243 |
7 | 3024550055614041 |
oct | 323030600116013 |
9 | 56314104570780 |
10 | 14503131520011 |
11 | 469181a713452 |
12 | 1762979499b23 |
13 | 812840ab4834 |
14 | 381d53532391 |
15 | 1a23d6904126 |
hex | d30c6009c0b |
14503131520011 has 12 divisors (see below), whose sum is σ = 20950362963192. Its totient is φ = 9668110402656.
The previous prime is 14503131519997. The next prime is 14503131520049. The reversal of 14503131520011 is 11002513130541.
14503131520011 is a `hidden beast` number, since 1 + 4 + 5 + 0 + 3 + 131 + 520 + 0 + 1 + 1 = 666.
It is not a de Polignac number, because 14503131520011 - 210 = 14503131518987 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14503131520811) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 53519341 + ... + 53789646.
It is an arithmetic number, because the mean of its divisors is an integer number (1745863580266).
Almost surely, 214503131520011 is an apocalyptic number.
14503131520011 is a deficient number, since it is larger than the sum of its proper divisors (6447231443181).
14503131520011 is a wasteful number, since it uses less digits than its factorization.
14503131520011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 107324010 (or 107324007 counting only the distinct ones).
The product of its (nonzero) digits is 1800, while the sum is 27.
Adding to 14503131520011 its reverse (11002513130541), we get a palindrome (25505644650552).
The spelling of 14503131520011 in words is "fourteen trillion, five hundred three billion, one hundred thirty-one million, five hundred twenty thousand, eleven".
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