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145035351353 is a prime number
BaseRepresentation
bin1000011100010011000…
…1111101010100111001
3111212100202121020020202
42013010301331110321
54334013022220403
6150343414531545
713323053100644
oct2070461752471
9455322536222
10145035351353
1156566747142
1224138066bb5
13108a4b4a539
14703c292a5b
153b8cd0c688
hex21c4c7d539

145035351353 has 2 divisors, whose sum is σ = 145035351354. Its totient is φ = 145035351352.

The previous prime is 145035351271. The next prime is 145035351361. The reversal of 145035351353 is 353153530541.

145035351353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105088133929 + 39947217424 = 324173^2 + 199868^2 .

It is a cyclic number.

It is not a de Polignac number, because 145035351353 - 212 = 145035347257 is a prime.

It is not a weakly prime, because it can be changed into another prime (145035354353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72517675676 + 72517675677.

It is an arithmetic number, because the mean of its divisors is an integer number (72517675677).

Almost surely, 2145035351353 is an apocalyptic number.

It is an amenable number.

145035351353 is a deficient number, since it is larger than the sum of its proper divisors (1).

145035351353 is an equidigital number, since it uses as much as digits as its factorization.

145035351353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 202500, while the sum is 38.

Adding to 145035351353 its reverse (353153530541), we get a palindrome (498188881894).

The spelling of 145035351353 in words is "one hundred forty-five billion, thirty-five million, three hundred fifty-one thousand, three hundred fifty-three".