1450404320033 has 4 divisors (see below), whose sum is σ = 1454584159920. Its totient is φ = 1446224480148.

The previous prime is 1450404320003. The next prime is 1450404320047. The reversal of 1450404320033 is 3300234040541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1450404320033 is a prime.

It is a super-3 number, since 3×1450404320033³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1450404319978 and 1450404320005.

It is not an unprimeable number, because it can be changed into a prime (1450404320003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2089919423 + ... + 2089920116.

It is an arithmetic number, because the mean of its divisors is an integer number (363646039980).

Almost surely, 2^{1450404320033} is an apocalyptic number.

It is an amenable number.

1450404320033 is a deficient number, since it is larger than the sum of its proper divisors (4179839887).

1450404320033 is an equidigital number, since it uses as much as digits as its factorization.

1450404320033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4179839886.

The product of its (nonzero) digits is 17280, while the sum is 29.

Adding to 1450404320033 its reverse (3300234040541), we get a palindrome (4750638360574).

The spelling of 1450404320033 in words is "one trillion, four hundred fifty billion, four hundred four million, three hundred twenty thousand, thirty-three".