Base | Representation |
---|---|
bin | 1000011100010100100… |
… | …0011110000001011001 |
3 | 111212101011201001000120 |
4 | 2013011020132001121 |
5 | 4334021030034231 |
6 | 150344145223453 |
7 | 13323154206201 |
oct | 2070510360131 |
9 | 455334631016 |
10 | 145041252441 |
11 | 5656a007778 |
12 | 2413a031b89 |
13 | 108a61354c7 |
14 | 703cd8b401 |
15 | 3b8d5c5d96 |
hex | 21c521e059 |
145041252441 has 4 divisors (see below), whose sum is σ = 193388336592. Its totient is φ = 96694168292.
The previous prime is 145041252439. The next prime is 145041252581. The reversal of 145041252441 is 144252140541.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 145041252441 - 21 = 145041252439 is a prime.
It is not an unprimeable number, because it can be changed into a prime (145041252241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24173542071 + ... + 24173542076.
It is an arithmetic number, because the mean of its divisors is an integer number (48347084148).
Almost surely, 2145041252441 is an apocalyptic number.
It is an amenable number.
145041252441 is a deficient number, since it is larger than the sum of its proper divisors (48347084151).
145041252441 is an equidigital number, since it uses as much as digits as its factorization.
145041252441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48347084150.
The product of its (nonzero) digits is 25600, while the sum is 33.
Adding to 145041252441 its reverse (144252140541), we get a palindrome (289293392982).
The spelling of 145041252441 in words is "one hundred forty-five billion, forty-one million, two hundred fifty-two thousand, four hundred forty-one".
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