Base | Representation |
---|---|
bin | 1101001100010000011101… |
… | …1111011100111111001101 |
3 | 1220100120221202002100020220 |
4 | 3103010013133130333031 |
5 | 3400114130420304201 |
6 | 50503052411101553 |
7 | 3024616226614620 |
oct | 323040737347715 |
9 | 56316852070226 |
10 | 14504230244301 |
11 | 4692233937256 |
12 | 17630254418b9 |
13 | 812987609955 |
14 | 38201941bdb7 |
15 | 1a244d0d7036 |
hex | d31077dcfcd |
14504230244301 has 16 divisors (see below), whose sum is σ = 22185721012224. Its totient is φ = 8256617756784.
The previous prime is 14504230244243. The next prime is 14504230244311. The reversal of 14504230244301 is 10344203240541.
It is not a de Polignac number, because 14504230244301 - 211 = 14504230242253 is a prime.
It is a super-2 number, since 2×145042302443012 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14504230244311) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1313069821 + ... + 1313080866.
It is an arithmetic number, because the mean of its divisors is an integer number (1386607563264).
Almost surely, 214504230244301 is an apocalyptic number.
It is an amenable number.
14504230244301 is a deficient number, since it is larger than the sum of its proper divisors (7681490767923).
14504230244301 is a wasteful number, since it uses less digits than its factorization.
14504230244301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2626150960.
The product of its (nonzero) digits is 46080, while the sum is 33.
Adding to 14504230244301 its reverse (10344203240541), we get a palindrome (24848433484842).
The spelling of 14504230244301 in words is "fourteen trillion, five hundred four billion, two hundred thirty million, two hundred forty-four thousand, three hundred one".
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