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145053351034001 = 791836118367519
BaseRepresentation
bin100000111110110011011101…
…011101100011110010010001
3201000120222001102202000002122
4200332303131131203302101
5123003023230331042001
61232300331201224025
742360521155251344
oct4076633535436221
9630528042660078
10145053351034001
1142244865142243
1214328389932015
1362c261a884927
1427b689646645b
1511b8285886b1b
hex83ecdd763c91

145053351034001 has 4 divisors (see below), whose sum is σ = 146889469401600. Its totient is φ = 143217232666404.

The previous prime is 145053351033977. The next prime is 145053351034057. The reversal of 145053351034001 is 100430153350541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-145053351034001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (145053351034901) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 918059183681 + ... + 918059183838.

It is an arithmetic number, because the mean of its divisors is an integer number (36722367350400).

Almost surely, 2145053351034001 is an apocalyptic number.

It is an amenable number.

145053351034001 is a deficient number, since it is larger than the sum of its proper divisors (1836118367599).

145053351034001 is an equidigital number, since it uses as much as digits as its factorization.

145053351034001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1836118367598.

The product of its (nonzero) digits is 54000, while the sum is 35.

The spelling of 145053351034001 in words is "one hundred forty-five trillion, fifty-three billion, three hundred fifty-one million, thirty-four thousand, one".

Divisors: 1 79 1836118367519 145053351034001