Base | Representation |
---|---|
bin | 100000111110111001110011… |
… | …101000000110011111110001 |
3 | 201000121121122100001222122011 |
4 | 200332321303220012133301 |
5 | 123003131204312103223 |
6 | 1232303415303442521 |
7 | 42361152061046116 |
oct | 4076716350063761 |
9 | 630547570058564 |
10 | 145060165347313 |
11 | 4224774169a737 |
12 | 1432976ba56441 |
13 | 62c3165575498 |
14 | 27b6d4148890d |
15 | 11b8533c2280d |
hex | 83ee73a067f1 |
145060165347313 has 2 divisors, whose sum is σ = 145060165347314. Its totient is φ = 145060165347312.
The previous prime is 145060165347269. The next prime is 145060165347341. The reversal of 145060165347313 is 313743561060541.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 86075568846864 + 58984596500449 = 9277692^2 + 7680143^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-145060165347313 is a prime.
It is not a weakly prime, because it can be changed into another prime (145060165347373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72530082673656 + 72530082673657.
It is an arithmetic number, because the mean of its divisors is an integer number (72530082673657).
Almost surely, 2145060165347313 is an apocalyptic number.
It is an amenable number.
145060165347313 is a deficient number, since it is larger than the sum of its proper divisors (1).
145060165347313 is an equidigital number, since it uses as much as digits as its factorization.
145060165347313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2721600, while the sum is 49.
The spelling of 145060165347313 in words is "one hundred forty-five trillion, sixty billion, one hundred sixty-five million, three hundred forty-seven thousand, three hundred thirteen".
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