14507131 has 2 divisors, whose sum is σ = 14507132. Its totient is φ = 14507130.

The previous prime is 14507117. The next prime is 14507147. The reversal of 14507131 is 13170541.

It is a weak prime.

It is an emirp because it is prime and its reverse (13170541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14507131 - 2⁵ = 14507099 is a prime.

It is a super-2 number, since 2×14507131² = 420913699702322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14517131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7253565 + 7253566.

It is an arithmetic number, because the mean of its divisors is an integer number (7253566).

Almost surely, 2^14507131 is an apocalyptic number.

14507131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14507131 is an equidigital number, since it uses as much as digits as its factorization.

14507131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 420, while the sum is 22.

The square root of 14507131 is about 3808.8227840108. The cubic root of 14507131 is about 243.8899160766.

Adding to 14507131 its reverse (13170541), we get a palindrome (27677672).

The spelling of 14507131 in words is "fourteen million, five hundred seven thousand, one hundred thirty-one".