Base | Representation |
---|---|
bin | 10101000111010100110… |
… | …010011100011000101011 |
3 | 12010201012212111212112011 |
4 | 111013110302130120223 |
5 | 142233043314101021 |
6 | 3030322423500351 |
7 | 206554326160234 |
oct | 25072462343053 |
9 | 5121185455464 |
10 | 1450973972011 |
11 | 50a399a86993 |
12 | 1b52602b76b7 |
13 | a6a9839c9a5 |
14 | 5032843008b |
15 | 27b23293de1 |
hex | 151d4c9c62b |
1450973972011 has 2 divisors, whose sum is σ = 1450973972012. Its totient is φ = 1450973972010.
The previous prime is 1450973971973. The next prime is 1450973972039. The reversal of 1450973972011 is 1102793790541.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1450973972011 - 213 = 1450973963819 is a prime.
It is a super-2 number, since 2×14509739720112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1450973972911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 725486986005 + 725486986006.
It is an arithmetic number, because the mean of its divisors is an integer number (725486986006).
Almost surely, 21450973972011 is an apocalyptic number.
1450973972011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1450973972011 is an equidigital number, since it uses as much as digits as its factorization.
1450973972011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 476280, while the sum is 49.
The spelling of 1450973972011 in words is "one trillion, four hundred fifty billion, nine hundred seventy-three million, nine hundred seventy-two thousand, eleven".
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