Base | Representation |
---|---|
bin | 1000011100100011010… |
… | …1010001101101100011 |
3 | 111212112111111220121212 |
4 | 2013020311101231203 |
5 | 4334132423031042 |
6 | 150354243540335 |
7 | 13324536645566 |
oct | 2071065215543 |
9 | 455474456555 |
10 | 145103330147 |
11 | 565a1057666 |
12 | 2415698a6ab |
13 | 108b5c5c089 |
14 | 704730a4dd |
15 | 3b93c89482 |
hex | 21c8d51b63 |
145103330147 has 2 divisors, whose sum is σ = 145103330148. Its totient is φ = 145103330146.
The previous prime is 145103330131. The next prime is 145103330227. The reversal of 145103330147 is 741033301541.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 145103330147 - 24 = 145103330131 is a prime.
It is not a weakly prime, because it can be changed into another prime (145103330447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72551665073 + 72551665074.
It is an arithmetic number, because the mean of its divisors is an integer number (72551665074).
Almost surely, 2145103330147 is an apocalyptic number.
145103330147 is a deficient number, since it is larger than the sum of its proper divisors (1).
145103330147 is an equidigital number, since it uses as much as digits as its factorization.
145103330147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 32.
Adding to 145103330147 its reverse (741033301541), we get a palindrome (886136631688).
The spelling of 145103330147 in words is "one hundred forty-five billion, one hundred three million, three hundred thirty thousand, one hundred forty-seven".
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