Base | Representation |
---|---|
bin | 1000011100100011110… |
… | …1010101011001100001 |
3 | 111212112122111020002111 |
4 | 2013020331111121201 |
5 | 4334133443124101 |
6 | 150354401115321 |
7 | 13324563624013 |
oct | 2071075253141 |
9 | 455478436074 |
10 | 145105442401 |
11 | 565a226a627 |
12 | 24157628b41 |
13 | 108b651b62a |
14 | 70476da1b3 |
15 | 3b94055251 |
hex | 21c8f55661 |
145105442401 has 2 divisors, whose sum is σ = 145105442402. Its totient is φ = 145105442400.
The previous prime is 145105442309. The next prime is 145105442407. The reversal of 145105442401 is 104244501541.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 72864904225 + 72240538176 = 269935^2 + 268776^2 .
It is an emirp because it is prime and its reverse (104244501541) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 145105442401 - 29 = 145105441889 is a prime.
It is not a weakly prime, because it can be changed into another prime (145105442407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72552721200 + 72552721201.
It is an arithmetic number, because the mean of its divisors is an integer number (72552721201).
Almost surely, 2145105442401 is an apocalyptic number.
It is an amenable number.
145105442401 is a deficient number, since it is larger than the sum of its proper divisors (1).
145105442401 is an equidigital number, since it uses as much as digits as its factorization.
145105442401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12800, while the sum is 31.
Adding to 145105442401 its reverse (104244501541), we get a palindrome (249349943942).
The spelling of 145105442401 in words is "one hundred forty-five billion, one hundred five million, four hundred forty-two thousand, four hundred one".
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