145115550233249 has 4 divisors (see below), whose sum is σ = 145122290723460. Its totient is φ = 145108809743040.

The previous prime is 145115550233239. The next prime is 145115550233263. The reversal of 145115550233249 is 942332055511541.

145115550233249 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 29553738232225 + 115561812001024 = 5436335^2 + 10749968^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-145115550233249 is a prime.

It is a super-2 number, since 2×145115550233249² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 145115550233197 and 145115550233206.

It is not an unprimeable number, because it can be changed into a prime (145115550233219) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3370212812 + ... + 3370255869.

It is an arithmetic number, because the mean of its divisors is an integer number (36280572680865).

Almost surely, 2^{145115550233249} is an apocalyptic number.

It is an amenable number.

145115550233249 is a deficient number, since it is larger than the sum of its proper divisors (6740490211).

145115550233249 is an equidigital number, since it uses as much as digits as its factorization.

145115550233249 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6740490210.

The product of its (nonzero) digits is 3240000, while the sum is 50.

The spelling of 145115550233249 in words is "one hundred forty-five trillion, one hundred fifteen billion, five hundred fifty million, two hundred thirty-three thousand, two hundred forty-nine".