145120414222321 has 4 divisors (see below), whose sum is σ = 149801717906944. Its totient is φ = 140439110537700.

The previous prime is 145120414222313. The next prime is 145120414222373. The reversal of 145120414222321 is 123222414021541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 145120414222321 - 2³ = 145120414222313 is a prime.

It is a super-3 number, since 3×145120414222321³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (145120414222921) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2340651842265 + ... + 2340651842326.

It is an arithmetic number, because the mean of its divisors is an integer number (37450429476736).

Almost surely, 2^{145120414222321} is an apocalyptic number.

It is an amenable number.

145120414222321 is a deficient number, since it is larger than the sum of its proper divisors (4681303684623).

145120414222321 is an equidigital number, since it uses as much as digits as its factorization.

145120414222321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4681303684622.

The product of its (nonzero) digits is 30720, while the sum is 34.

Adding to 145120414222321 its reverse (123222414021541), we get a palindrome (268342828243862).

The spelling of 145120414222321 in words is "one hundred forty-five trillion, one hundred twenty billion, four hundred fourteen million, two hundred twenty-two thousand, three hundred twenty-one".