Search a number
-
+
145142113 is a prime number
BaseRepresentation
bin10001010011010…
…11000101100001
3101010002222112211
420221223011201
5244124021423
622222522121
73411454564
oct1051530541
9333088484
10145142113
1174a24466
1240736341
13240baa0c
14153c24db
15cb2010d
hex8a6b161

145142113 has 2 divisors, whose sum is σ = 145142114. Its totient is φ = 145142112.

The previous prime is 145142089. The next prime is 145142147. The reversal of 145142113 is 311241541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 138956944 + 6185169 = 11788^2 + 2487^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-145142113 is a prime.

It is a super-2 number, since 2×1451421132 = 42132465932209538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (145140113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72571056 + 72571057.

It is an arithmetic number, because the mean of its divisors is an integer number (72571057).

Almost surely, 2145142113 is an apocalyptic number.

It is an amenable number.

145142113 is a deficient number, since it is larger than the sum of its proper divisors (1).

145142113 is an equidigital number, since it uses as much as digits as its factorization.

145142113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 480, while the sum is 22.

The square root of 145142113 is about 12047.4940547817. The cubic root of 145142113 is about 525.5303641121.

Adding to 145142113 its reverse (311241541), we get a palindrome (456383654).

The spelling of 145142113 in words is "one hundred forty-five million, one hundred forty-two thousand, one hundred thirteen".