14519811041 has 4 divisors (see below), whose sum is σ = 14575019712. Its totient is φ = 14464602372.

The previous prime is 14519811037. The next prime is 14519811071. The reversal of 14519811041 is 14011891541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14011891541 = 197 ⋅71126353.

It is a cyclic number.

It is not a de Polignac number, because 14519811041 - 2² = 14519811037 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14519810992 and 14519811010.

It is not an unprimeable number, because it can be changed into a prime (14519811011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27603941 + ... + 27604466.

It is an arithmetic number, because the mean of its divisors is an integer number (3643754928).

Almost surely, 2^14519811041 is an apocalyptic number.

It is an amenable number.

14519811041 is a deficient number, since it is larger than the sum of its proper divisors (55208671).

14519811041 is an equidigital number, since it uses as much as digits as its factorization.

14519811041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55208670.

The product of its (nonzero) digits is 5760, while the sum is 35.

The spelling of 14519811041 in words is "fourteen billion, five hundred nineteen million, eight hundred eleven thousand, forty-one".