Base | Representation |
---|---|
bin | 1101001101001011101100… |
… | …0010001111010000010011 |
3 | 1220102002222122100211212121 |
4 | 3103102323002033100103 |
5 | 3400344210102333033 |
6 | 50514242054035111 |
7 | 3026021202241444 |
oct | 323227302172023 |
9 | 56362878324777 |
10 | 14520127386643 |
11 | 4698a5140961a |
12 | 1766121348a97 |
13 | 81431bc8b758 |
14 | 382ac68572cb |
15 | 1a2a7da6162d |
hex | d34bb08f413 |
14520127386643 has 2 divisors, whose sum is σ = 14520127386644. Its totient is φ = 14520127386642.
The previous prime is 14520127386619. The next prime is 14520127386659. The reversal of 14520127386643 is 34668372102541.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14520127386643 - 213 = 14520127378451 is a prime.
It is not a weakly prime, because it can be changed into another prime (14520127386943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7260063693321 + 7260063693322.
It is an arithmetic number, because the mean of its divisors is an integer number (7260063693322).
Almost surely, 214520127386643 is an apocalyptic number.
14520127386643 is a deficient number, since it is larger than the sum of its proper divisors (1).
14520127386643 is an equidigital number, since it uses as much as digits as its factorization.
14520127386643 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5806080, while the sum is 52.
The spelling of 14520127386643 in words is "fourteen trillion, five hundred twenty billion, one hundred twenty-seven million, three hundred eighty-six thousand, six hundred forty-three".
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