Base | Representation |
---|---|
bin | 100001000000111110011001… |
… | …011110010010100110010001 |
3 | 201001010020010021020121002121 |
4 | 201000332121132102212101 |
5 | 123012444242230333132 |
6 | 1232453042351014241 |
7 | 42404352105432136 |
oct | 4100763136224621 |
9 | 631106107217077 |
10 | 145202534230417 |
11 | 422a205a172804 |
12 | 14351282b0a381 |
13 | 6303703b49951 |
14 | 27bdba955658d |
15 | 11bc0b78c0497 |
hex | 840f99792991 |
145202534230417 has 2 divisors, whose sum is σ = 145202534230418. Its totient is φ = 145202534230416.
The previous prime is 145202534230387. The next prime is 145202534230493. The reversal of 145202534230417 is 714032435202541.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 144899985828481 + 302548401936 = 12037441^2 + 550044^2 .
It is a cyclic number.
It is not a de Polignac number, because 145202534230417 - 239 = 144652778416529 is a prime.
It is not a weakly prime, because it can be changed into another prime (145202534230717) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72601267115208 + 72601267115209.
It is an arithmetic number, because the mean of its divisors is an integer number (72601267115209).
Almost surely, 2145202534230417 is an apocalyptic number.
It is an amenable number.
145202534230417 is a deficient number, since it is larger than the sum of its proper divisors (1).
145202534230417 is an equidigital number, since it uses as much as digits as its factorization.
145202534230417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 806400, while the sum is 43.
Adding to 145202534230417 its reverse (714032435202541), we get a palindrome (859234969432958).
The spelling of 145202534230417 in words is "one hundred forty-five trillion, two hundred two billion, five hundred thirty-four million, two hundred thirty thousand, four hundred seventeen".
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